簡単なの解く

//AOJ0549
#include<iostream>
#include<cstdio>
#include<cstdlib>
using namespace std;
int n,m,k,ans;
int d[100000];
int p; 
int main(){
	scanf("%d %d",&n,&m);
	for(int i = 1; i < n;i++){
		scanf("%d", &k);
		d[i] = d[i-1] + k;
	}
	for(int i = 0; i < m;i++){
		scanf("%d",&k);
		ans = (ans + abs(d[p] - d[p+k])) % 100000;
		p += k;
	}
	printf("%d\n", ans);
	return 0;
}